(x-1)^3 Expand

3 min read Jul 03, 2024
(x-1)^3 Expand

(x-1)^3 Expansion

In algebra, expanding an expression involving exponents and binomials can be a bit tricky. One common expansion is the cube of a binomial, specifically, (x-1)^3. In this article, we will learn how to expand this expression using the binomial theorem.

The Binomial Theorem

The binomial theorem is a mathematical formula for expanding powers of a binomial, which is an expression consisting of two terms. The theorem states that:

$(a+b)^n = \sum_{k=0}^n \binom{n}{k} a^{n-k} b^k$

where n is a positive integer, a and b are variables, and k is an integer that ranges from 0 to n. The binomial coefficient binom(n,k) is calculated as:

$\binom{n}{k} = \frac{n!}{k!(n-k)!}$

Expanding (x-1)^3

Using the binomial theorem, we can expand (x-1)^3 as follows:

$(x-1)^3 = \sum_{k=0}^3 \binom{3}{k} x^{3-k} (-1)^k$

Let's calculate each term:

  • k=0: $\binom{3}{0} x^3 (-1)^0 = x^3$
  • k=1: $\binom{3}{1} x^2 (-1)^1 = -3x^2$
  • k=2: $\binom{3}{2} x^1 (-1)^2 = 3x$
  • k=3: $\binom{3}{3} x^0 (-1)^3 = -1$

Now, combine the terms:

$(x-1)^3 = x^3 - 3x^2 + 3x - 1$

Conclusion

In this article, we have successfully expanded (x-1)^3 using the binomial theorem. The expansion is a cubic expression with four terms. This expansion is useful in various algebraic manipulations and applications in mathematics, physics, and engineering.

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