(x-1)^3 Expansion
In algebra, expanding an expression involving exponents and binomials can be a bit tricky. One common expansion is the cube of a binomial, specifically, (x-1)^3
. In this article, we will learn how to expand this expression using the binomial theorem.
The Binomial Theorem
The binomial theorem is a mathematical formula for expanding powers of a binomial, which is an expression consisting of two terms. The theorem states that:
$(a+b)^n = \sum_{k=0}^n \binom{n}{k} a^{n-k} b^k$
where n
is a positive integer, a
and b
are variables, and k
is an integer that ranges from 0 to n
. The binomial coefficient binom(n,k)
is calculated as:
$\binom{n}{k} = \frac{n!}{k!(n-k)!}$
Expanding (x-1)^3
Using the binomial theorem, we can expand (x-1)^3
as follows:
$(x-1)^3 = \sum_{k=0}^3 \binom{3}{k} x^{3-k} (-1)^k$
Let's calculate each term:
k=0
:$\binom{3}{0} x^3 (-1)^0 = x^3$
k=1
:$\binom{3}{1} x^2 (-1)^1 = -3x^2$
k=2
:$\binom{3}{2} x^1 (-1)^2 = 3x$
k=3
:$\binom{3}{3} x^0 (-1)^3 = -1$
Now, combine the terms:
$(x-1)^3 = x^3 - 3x^2 + 3x - 1$
Conclusion
In this article, we have successfully expanded (x-1)^3
using the binomial theorem. The expansion is a cubic expression with four terms. This expansion is useful in various algebraic manipulations and applications in mathematics, physics, and engineering.